The coordinates are a pair of numbers that are used to locate points on a plane. x-coordinate is the distance between two points on the y-axis. y-coordinate is the distance between two points on the x-axis.
Representation of (x,y) on the cartesian plane
The distance between two points that are on the same axis (x-axis or y-axis), is given by the difference between their ordinates if they are on the y-axis, else by the difference between their abscissa if they are on the x-axis.
Distance AB = 6 – (-2) = 8 units
Distance CD = 4 – (-8) = 12 units
Let P(x1, y1) and Q(x2, y2) be any two points on the cartesian plane.
ΔPTQ is right-angled at T.
By Pythagoras Theorem,
PQ2 = PT2 + QT2=>(x2 – x1)2 + (y2 – y1)2PQ = √[x2 – x1)2 + (y2 – y1)2]
If the point P(x, y) divides the line segment joining A(x1, y1) and B(x2, y2) internally in the ratio m:n, then, the coordinates of P are given by the section formula as:
The midpoint of any line segment divides it in the ratio 1 : 1.The coordinates of the midpoint(P) of line segment joining A(x1, y1) and B(x2, y2) is given by: p(x, y)=(x1+x2/2 , y1+y2/2)
To find the points of trisection P and Q which divides the line segment joining A(x1, y1) and B(x2, y2) into three equal parts:
If A(x1, y1), B(x2, y2) and C(x3, y3) are the vertices of a ΔABC, then the coordinates of its centroid(P) is given by:
If A(x1, y1),B(x2, y2) and C(x3, y3) are the vertices of a Δ ABC, then its area is given by: A = (1/2)[x1(y2 − y3) + x2(y3 − y1) + x3(y1 − y2)]
Where A is the area of the Δ ABC.
Co-linearity condition-
Three or more points that lie on a same straight line are called collinear points. If three points A, B and C are collinear and B lies between A and C, then:
AB + BC = AC. AB, BC, and AC can be calculated using the distance formula.
The ratio in which B divides AC, calculated using section formula for both the x and y coordinates separately will be equal.
Area of a triangle formed by three collinear points is zero.
Table of Contents